在xsl任何接收http://community.csdn.net/Expert/topic/3091/3091367.xml?temp=.2425196形式的参数？saucer回答：
There Is So General Solution, If You Are Using IE6, You Can Try The Following, But You Have To Parse The URL First，下面是完整的xsl代码：
<![CDATA[
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:user="whatever">
<msxsl:script implements-prefix="user" language="Javascript">
<![CDATA[
function getDocURL(nodelist,sName) {
if (sName == null)
return "";
var url = nodelist.nextNode().url;
var re = new RegExp("[?&]" + sName + "=([^&]*|$)","i");
if (re.test(url))
return RegExp.$1;
else
return "";
}
]]]]><![CDATA[>
</msxsl:script>
<xsl:output method="text" indent="yes"/>
<xsl:template match="/">
****<xsl:value-of select="user:getDocURL(/,'varid')"/>****
</xsl:template>
</xsl:stylesheet>
]]>
通过访问：http://server/xx.xml?varid=yyyy，你可以看到下面的输出：
****yyyy****
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